Make random word use the dictionary instead of auxiliar array. #22

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Ghost · 2022-06-11T16:26:26+09:00

Ghost commented

2022-06-11 16:26:26 +09:00

Also if posible make it search a heonian word, i think that whould be feature not refactor. But i prefer comenting here than makign another issue

Ghost added the

refactoring

label 2022-06-11 16:26:26 +09:00

lustlion added the

enhancement

label 2022-06-11 16:33:47 +09:00

lustlion commented

2022-06-11 16:51:25 +09:00

Please use these

function randint(bound) {
    return Math.floor(Math.random() * bound);
}

function randitem(array) {
    return array[randint(array.length)];
}

Please use these ``` function randint(bound) { return Math.floor(Math.random() * bound); } function randitem(array) { return array[randint(array.length)]; } ```

Ghost commented

2022-06-11 16:56:46 +09:00

We surelly need one of those but need the second one to be changed to a dictionary instead of the array to fulfill the issue i posted :P

Please use these

function randint(bound) {
    return Math.floor(Math.random() * bound);
}

function randitem(array) {
    return array[randint(array.length)];
}

We surelly need one of those but need the second one to be changed to a dictionary instead of the array to fulfill the issue i posted :P > Please use these > > ``` > function randint(bound) { > return Math.floor(Math.random() * bound); > } > > function randitem(array) { > return array[randint(array.length)]; > } > ```

remi closed this issue

2022-06-12 06:01:07 +09:00

remi commented

2022-06-12 06:01:19 +09:00

doen in 0e8ac06e26 . i htink

doen in 0e8ac06e26 . i htink

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